100W SMT PLANAR TRANSFORMER AND INDUCTOR ® For use with Texas Instrument’s UCC3580 PLANAR TRANSFORMER – PA0369 Power Rating: 100W (48v to 3.3v/30A) Height: 8.4mm Max Footprint: 23.4mm x 20.1mm Max PLANAR INDUCTOR – PA0373 Energy Storage: up to 900µJ (2.0µH/30Adc) Height: 7.4mm Max Footprint: 23.4mm x 20.1mm Max Electrical Specifications @ 25°C — Operating Temperature -40°C to 125°C Primary Primary Leakage DCR Part Power Turns Ratio Secondary Inductance Inductance Primary Secondary 2 Number Rating (Pri:Sec) Isolation (µH MIN) (µH MAX) (mΩ MAX) (mΩ MAX) PA0369 100 W (3.3v/30A) 6:1 1500 Vdc Basic 65 .25 15 0.4 Electrical Specifications @ 25°C — Operating Temperature -40°C to 125°C 4 3 DCR (mΩ MAX) Saturation Current Inductance Turns Ratio Inductance Heating Part Irated 5 (A) @Irated (7-11) (Main Winding @ 0 A Current DC Main Winding Aux. Winding Number (A ) DC (A) (µH ±10%) to Aux.) (µH ±10%) @ 25°C @ 100°C (7-11) (1-6) PA0373 2.0 30 1:4 2.1 2800 2.1 44 35.2 34 Mechanicals Schematics PA0369 �������������������� � � �������� �������� ������ � � ��������� ����������������� PA0373 �������������������� �� � ����� !"� �����#�� � � PA0369 PA0373 Weight ..................11.0 grams ..................11.0 grams ������ ��������� Tape & Reel...............180/reel.......................250/reel ����������������� Tray.............................40/tray.........................90/tray Inches Dimensions: mm .010 Unless otherwise specified, all tolerances are ± 0,25 • • • • • • • • • • • • US 619 674 8100 UK 44 1483 401 700 France 33 3 84 35 04 04 Singapore 65 6287 8998 Taiwan 886 2 2698 0228 Hong Kong 852 2788 6588 http://www.pulseeng.com P571.B (12/02) NEW! 100W SMT PLANAR TRANSFORMER AND INDUCTOR ® For use with Texas Instrument’s UCC3580 Notes from Tables 1. The PA0369 transformer and PA0373 inductor were designed For P0373: Planar Inductor ® for use with Texas Instrument's UCC3580 IC and form the 3. The rated current as listed is either 85% of the saturation cur- rent or the heating current depending on which value is lower. foundation of a low cost, discrete component alternative to tele- com power modules. The PA0369 transformer and PA0373 4. The saturation current is the current which causes the induc- inductor were designed for (but not limited to) the following tance to drop by 15% at the stated ambient temperatures applications: (25°C, 100°C). This current is determined by placing the com- Topology: Single switch Forward ponent in the specified ambient environment and applying a Frequency: 300kHz short duration pulse current (to eliminate self-heating effects) to the component. Pri./Sec. Isolation: Basic Insulation (1500Vdc) Input Voltage: 36-75v telecom input 5. The heating current is the dc current which causes the temper- Output Voltage: 3.3v / 30A output ature of the part to increase by approximately 45°C. This cur- rent is determined by mounting the component on a PCB with a For PA0369: Basic Insulated Planar Transformer: .25" wide, 2oz. Equivalent copper traces, and applying the cur- 2. To determine if the transformer is suitable for your application, it rent to the device for 30 minutes with no force air cooling. is necessary to ensure that the temperature rise of the compo- 6. In high volt*time applications additional heating in the compo- nent (ambieint plus temp. rise) does not exceed its operating nent can occur due to core losses in the inductor which may temperature.To determine the temperature rise of the compo- neccessitate derating the current in order to limit the tempera- nent it is necessary to calculate the total power losses (core ture rise of the component. In order to determine the approxi- and copper) in the application. mate total losses (or temperature rise) for a given application both copper an core losses should be taken into account Total Copper Losses (Pcu total(W)): Pcu total(W) = sum of the losses in each winding Total Copper Losses (Pcu_total(W)): 2 The losses in each winding can be calculated by: Pcu(W)= .001* DCR(mΩ) * (Irms ) 2 where: Pcu(W) = .001* DCR(mΩ) * (Irms ) 2 2 .5 Irms = (Idc + (∆1/2) ) Core Losses (Pcore(W)) ∆1 = ripple current through inductor To calculate core loss, use the following formula: -13 2.5 1.8 Core Losses (Pcore(W)): CoreLoss (W) = 1.92 * 10 (∆B) * (Freq kHz) Use the Inductor Voltage versus CoreLoss table to where: determine the approximate core losses ∆B = 22653.1 * Vin min * Dutycycle max / Freq kHz Total Losses: Total Losses: P total = Pcu total + CoreLoss P total = Pcu total + CoreLoss Temperature Rise: The approximate temperature rise can be found by looking Temperature Rise: up the calculated total losses in the temperature rise vs. The approximate temperature rise can be found by looking power dissipation curve. up the calculated total losses in the temperature rise vs. power dissipation curve. ® 7. UCC3580 is a registered trademark of Texas Instruments. ��!"��������#$������ ������������������������������ ��&’(’���������������������� ��%����� ��$��$"��$�� �� ��� ��� ��� �� ��� �� �� ��� �� ��� �� �� ��� � �� ��� � � ��� � � ��� ��� ��� ��� ��� ��� �� �� �� �� �� �� �� �� �� ������������ ���������� ��������%����� ��$��$"��$�� ���� ��� For More Information : UNITED STATES UNITED KINGDOM FRANCE SINGAPORE TAIWAN, R.O.C. HONG KONG DISTRIBUTOR (Worldwide) (Northern Europe) (Southern Europe) (Southern Asia) (Northern Asia) (China/Hong Kong) 1 & 2 Huxley Road 12220 World Trade Drive Zone Industrielle 150 Kampong Ampat 3F-4, No. 81, Sec. 1 19/F, China United Plaza The Surrey Research Park San Diego, CA 92128 F-39270 #07-01/02 HsinTai Wu Road 1008 Tai Nan West Street Guildford, Surrey GU2 5RE U.S.A. Orgelet KA Centre Hsi-Chih, Taipei Hsien Cheung Sha Wan, Kowloon United Kingdom http://www.pulseeng.com France Singapore 368324 Taiwan, R.O.C. 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